On Sun, 07 Oct 2007 10:41:52 +0200, Marco Costalba <mcostalba@???>
wrote:
>
> I would think to fix completely the problem reported by Joel we could
> write instead:
>
> boost::is_convertible<F, boost::function<T> >
>
> But for unknown reasons this fails! All types of function pointers match!
>
> Could someone please be so kind to enlight me?
>
> Thanks
> Marco
Because boost::function has a constructor whose behavior is like this:
template< typename Functor >
function (Functor const& f)
it skips only integral type through enable_if.
So, except integral, everything is convertible to boost::function even
apples.
In order to implement signature deduction I exploits a support utility
used in the implementation of boost::function and a lot of metaprogramming.
Give a glance to detail::function::get_function_tag in function_base.hpp,
in order to learn how to discern between different kind of functors.
Regard,
Marco Cecchetti
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